contestada

Ammonia (nh3(g), hf = –46.19 kj/mol) reacts with hydrogen chloride (hcl(g), hf = –92.30 kj/mol) to form ammonium chloride (nh4cl(s), hf = –314.4 kj/mol) according to this equation:

Respuesta :

-175.9 kJ hope this question

The enthalpy of the reaction for the formation of ammonium chloride has been -175.91 kJ/mol.

The complete question has been termed to find the enthalpy of the reaction.

The enthalpy of the reaction has been termed as the difference in the enthalpy with the formation and the breaking of the bonds in the reaction.

The enthalpy of reaction = Enthalpy of formation - enthalpy of bond breaking.

The given balanced reaction has been:

[tex]\rm NH_3\;+HCl\;\rightarrow\;NH_4Cl[/tex]

The enthalpy of formation has been opposite to the enthalpy of breaking bonds.

The enthalpy for breaking bonds of reactants:

Enthalpy for ammonia + Enthalpy for Hydrogen chloride

= -46.19 kJ/mol + 92.30 kJ/mol

= -138.49 kJ/mol

The enthalpy of bond formation of product:

= -314.4 kJ/mol

The enthalpy of reaction =  Enthalpy of formation - enthalpy of bond breaking.

= -314.49 kJ/mol - (138.49 kJ/mol)

= -175.91 kJ/mol.

The enthalpy of the reaction for the formation of ammonium chloride has been -175.91 kJ/mol.

For more information about the enthalpy of reaction, refer to the link:

https://brainly.com/question/11753370

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