Answer: The correct option is (A) 42.7 units.
Step-by-step explanation: Given that the radius of the circle center at O is 24 units and OC is 11 units.
We are to find the length of chord AB.
We have,
in the right-angled triangle OCB (m∠OCB = 90°),
OB = 24 units and OC = 11 units.
Using Pythagoras theorem in ΔOCB, we have
[tex]OB^2=OC^2+BC^2\\\\\Rightarrow BC=\sqrt{OB^2-OC^2}\\\\\Rightarrow BC=\sqrt{24^2-11^2}\\\\\Rightarrow BC=\sqrt{576-121}\\\\\Rightarrow BC=\sqrt{455}\\\\\Rightarrow BC=21.33.[/tex]
Since OC is perpendicular to chord AB, so AC = BC.
Therefore, we get
[tex]AB=AC+BC=2\times BC=2\times 21.33=42.66=42.7.[/tex]
Thus, the required length of AB is 42.7 units.
Option (A) is CORRECT.
