Respuesta :

gmany
[tex]\dfrac{20xy^3}{6z}:\dfrac{2xy}{18z^5}=\dfrac{10xy^3}{3z}:\dfrac{xy}{9z^5}=\dfrac{10xy^3}{3z}\cdot\dfrac{9z^5}{xy}\\\\=\dfrac{10xy^3}{z}\cdot\dfrac{3z^5}{xy}=10y^2z^4\\\\\text{used:}\\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}[/tex]

Otras preguntas