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Chandra wants to know how many moles are contained in 150.0g CCl4 what quantity of CCl4 should she use to make this conversion

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Willchemistry
hey there!:

atomic mass :

C = 12.01070 amu

Cl = 35.4530 amu

Molar mass:

CCl4 = ( 1 * 12.01070 ) + ( 35.4530 *4 ) = 153.8227 g/mol

Therefore:

n = mass of solute / molar mass

n = 150.0 / 153.8227

n = 0.975 moles

hope this helps!
amovoce

Answer:

Molar mass.

Explanation:

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