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Given the exponential equation 2x = 128, what is the logarithmic form of the equation in base 10? x = log base 2 of 2, all over log base 2 of 128 x = log base 2 of 128, all over log base 2 of 2 x = log base 10 of 2, all over log base 10 of 128 x = log base 10 of 128, all over log base 10 of 2

Respuesta :

Given exponential equation is [tex] 2^x=128 [/tex]

Now question says to write the given exponential equation in logarithmic form.

To do that we use the following conversion formula

[tex] a^b=c \Rightarrow \log_{a}c=b [/tex]


In this formula we see that base "a" remains at it's position but b and c switch.

So we will keep base "2" fixed at it's position and switch x with 128.

Hence final answer will be

[tex] \log_{2}128 = x [/tex]

Answer:

logx128 = 2

Step-by-step explanation:

you switch the sides. the guy above me is not right

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