Given below the arrangement of loading on the larger boat by two tug boats.
F₁ = 5 N
F₂ = 4 N
Angle between them θ = 90⁰
Resultant between two vectors, [tex]F=\sqrt{F_1^2+F_2^2+2F_1F_2cos\theta }[/tex]
Substituting
[tex]F = \sqrt{5^2+4^2+2*5*4*cos 90} \\ \\ = 6.403 N[/tex]
So magnitude of the net force on the block = 6.403 N
