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Two planes left the same airport traveling in opposite directions. The first plane left at 9:00 a.m. and 2.25 hours later, the two planes were 1825 miles apart. The second plane left at 10:00 a.m. and its average rate was 108 miles per hour slower than the first plane's average rate. Let x represent the first plane's average rate. What was the first plane's average rate? Enter an equation that can be used to solve this problem in the first box. Solve for x and enter the first plane's average rate in the second box.

WHAT IS THE EQUATION AND WHAT IS THE ANSWERRR???

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Respuesta :

allycat3345 allycat3345 · Answer 1 · 2018-10-10T22:12:35+02:00

Answer:

The Average rate of the first plane is 560 mph

Step-by-step explanation:

x = first plane's average rate (in mph)

x−108 = second plane's average rate (in mph)

First planes total distance = 2.25x

Second planes total distance = 1.25(x−108)

2.25x + 1.25(x−108) = 1825

x = 560

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