Respuesta :
Answer: 12 nickels, 8 dimes, 3 quarters
Step-by-step explanation:
[tex]\begin {array}{l|c|c||l}&\underline{Value}&\underline{Quantity}&\underline{\qquad Total\ Value\qquad }\\ Nickels&\$ 0.05&4+d&0.05(4+d)=0.20+0.05d\\Dimes&\$ 0.10&d&\qquad 0.10(d)=0.10d\\Quarters&\$ 0.25&d-5&0.25(d-5)=0.25d-1.25\\\end{array}[/tex]
Nickels + Dimes + Quarters = Total
0.20 + 0.05d + 0.10d + 0.25d - 1.25 = 2.15
0.40d - 1.05 = 2.15
0.40d = 3.20
d = 8
Nickels: 4 + d = 4 + (8) = 12
Quarters: d - 5 = (8) - 5 = 3
Check:
Nickels: 0.05(12) = $0.60
Dimes: 0.10 (8) = $0.80
Quarters: 0.25(3) = $0.75
Total: = $2.15 [tex]\checkmark[/tex]
There are [tex]\boxed{12{\text{ nickel coins}}}, \boxed{8{\text{ dime coins}}}[/tex] and [tex]\boxed{3{\text{ quarter coins}}}.[/tex]
Further explanation:
Given:
Adam has [tex]\$ 2.15[/tex] in nickels, dimes and quarters.
Explanation:
Let us consider the number of coins of nickels as [tex]\text{x}[/tex], the number of coins of dimes as [tex]\text{y}[/tex] and the number of coins of quarters are [tex]\text{z}[/tex].
[tex]\boxed{1{\text{ nickel}} = \$ 0.05}.[/tex]
[tex]\boxed{1{\text{ dime}} = \$ 0.05}.[/tex]
[tex]\boxed{1{\text{ quarter}} = \$ 0.05}.[/tex]
If the number of dimes is 4 less than the number of nickels
[tex]x = \left( {4 + y} \right)[/tex]
If the number of dimes 5 more than the number of quarters
[tex]z = y - 5[/tex]
Adam has [tex]\$ 2.15[/tex] in nickels, dimes and quarters.
[tex]\begin{aligned}0.05x + 0.10y + 0.25z &= 2.15 \\0.05\left( {4 + y} \right) + 0.10y + 0.25\left( {y - 5} \right) &= 2.15\\0.40y - 1.05 &= 2.15\\0.40y&= 3.20\\y&= 8\\\end{aligned}[/tex]
Number of coins of nickels are 12.
Number of coins of quarters are 3.
There are [tex]\boxed{12{\text{ nickel coins}}}, \boxed{8{\text{ dime coins}}}[/tex] and [tex]\boxed{3{\text{ quarter coins}}}.[/tex]
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Polynomial
Keywords: Adam, $2.15, nickels, dimes, quarters, pocket, number, less, less than, 5 more than, coin, number of quarters.