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The mass of an Erlenmeyer flask is 85.135 g. After 10.00 mL of water is added to the flask, the mass of the flask and the water is 95.023 g. Calculate the density (in g/mL) of water.

Using the density calculated in the question above, calculate the percent error if the true density at this temperature is 0.9992 g/mL.

Respuesta :

jcherry99

Once the water has been added, the mass of the water is calculated to be

(Mass of flask + water) - mass of the flask

mass water = 95.023 - 85.135 = 9.888

Density = mass / volume

Density = 9.888 / 10 = 0.9888

% error = [(what it should be - what it is)/(what it should be)]  * 100

% error = (0.9992 - 0.9888) / 0.9992   * 100 = 0.04003 % error.

Answer:

The density (in g/mL) of water is 0.09888 g/mL.

The percentage error is 1.04%.

Explanation:

The mass of an Erlenmeyer flask  = m = 85.135 g

The mass of an Erlenmeyer flask and 100 mL of water ,M= 95.023 g

Mass of 10 mL water ,x= M - m = 95.023 g - 85.135 g = 9.888 g[/tex]

Mass of the wate ,x = 9.888 g

Volume of the water  = V = 10 mL

Density of the water,d = [tex]\frac{x}{V}=\frac{9.888}{10 mL}=0.9888 g/ml[/tex] (calculated value)

The density (in g/mL) of water is 0.9888 g/mL.

True density of the water , D'= 0.9992 g/mL(theoretical value)

The percent error can be calculated as:

[tex]\% error=\frac{|Experimental - Theoretical|}{Theoretical}\times 100[/tex]

[tex]\% error=\frac{|0.9888 g/ml-0.9992 g/mL|}{0.9992 g/mL}\times 100[/tex]

[tex]=1.04\%[/tex]

The percentage error is 1.04%.