Noah thinks the answers to these two questions will be the same. Do you agree with him? Explain your reasoning. This year, a herd of bison had a 10% increase in population. If there were 550 bison in the herd last year, how many are in the herd this year? This year, another herd of bison had a 10% decrease in population. If there are 550 bison in the herd this year, how many bison were there last year?

Respuesta :

Answer: No, She is not right.

Step-by-step explanation:

First question:

Initial number of bison = 550

After increasing 10% than the initial number of bison, the new number of bison after one year= Initial number of bison + 10 % of the initial number of bison

= [tex]110\% \text{ of the initial number of bison}[/tex]

= [tex]110\% \text{ of }550[/tex]

= [tex]\frac{110\times 550}{100}[/tex]

=  [tex]\frac{60500}{100}[/tex]

= [tex]605[/tex]

Second question:

Let Initial number of bison = x

After decreasing 10% than the initial number of bison, the new number of bison after one year= Initial number of bison - 10 % f the initial number of bison

= [tex]90\% \text{ of the initial number of bison}[/tex]

= [tex]90\% \text{ of } x[/tex]

= [tex]\frac{90\times x}{100}[/tex]

=  [tex]\frac{9x}{10}[/tex]

According to the question,

[tex]\frac{9x}{10}=550[/tex]

[tex]x=\frac{5500}{9}=611.11\approx 611[/tex]

Since, 605 ≠ 611

Therefore, Both questions have different answer.

Noah is not correct.

Answer: NO

Step-by-step explanation: