Answer:
Step-by-step explanation:
Given: PQRS is a parallelogram and the coordinates of P and S are (-1,6) and (-7,-3) respectively.
To find: The slope of QR.
Solution: The coordinates of P and S are (-1,6) and (-7,-3) respectively.
Then, Slope Of PS=[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
=[tex]\frac{-3-6}{-7+1}[/tex]
=[tex]\frac{-9}{-6}[/tex]
=[tex]\frac{3}{2}[/tex]
Thus, Slope of PS=[tex]\frac{3}{2}[/tex].
Now, since it is given that PQRS is a parallelogram, thus Slope of PS will be equal to the slope of QR, thus slope of QR=[tex]\frac{3}{2}[/tex].
