Write an equation of the circle given its center and radius

y = x²- 4x + 3 + y²
The equation of a circle is given by the formula
(x-a)²+(x-b)² = r²
Where; (a, b) is the center of the circle and r is the radius
Center (2,0) and radius = 1.
Therefore:
(x-2)² +(y+0) = 1²
x²- 4x + 4 + y² = 1
x²- 4x + 3 + y² = 0
Therefore; The equation of the circle is y = x²- 4x + 3 + y²
Answer:
(x-2)²+ y² = 1 is the equation of given circle.
Step-by-step explanation:
We have given the center (2,0) and radius r = 1 of a circle.
We have to find the equation of circle.
As we know the equation of circle is :
(x - x₁)² +(y - y₁)² = r²
Where (x₁,y₁) is the center of circle, and r is the radius of the circle.
Putting the value in above equation we get,
(x-2)²+(y-0)² = 1²
(x-2)²+ y² = 1 is the equation of given circle.