Respuesta :

frika

Answer:

[tex](x-2)^2+(y-3)^2=0.25.[/tex]

Step-by-step explanation:

If the center of the circle is (2,3) and the diameter of the circle is 1, then the radius is [tex]\dfrac{1}{2}.[/tex]

The equation of the circle with center [tex](x_0,y_0)[/tex] and radius r is

[tex](x-x_0)^2+(y-y_0)^2=r^2.[/tex]

In your case, the equation is

[tex](x-2)^2+(y-3)^2=0.25.[/tex]

zainebamir540

Answer:

(x-2)²+(y-3)² = 0.25

Step-by-step explanation:

We have given that

Center  = (2,3)  ; Diameter  = 1

We have to find the equation of circle.

The equation of circle is :

(x-h)²+(y-k)²  = r² where (h,k) is the center of circle and r is the radius.

d   =  r/2

d   = 1/2  = 0.5

(h,k)  = (2,3)

Putting values in above equation, we have

(x-2)²+(y-3)² = (0.5)²

(x-2)²+(y-3)² = 0.25 which is equation of circle.

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