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//SUPER EASY/////.
A group of 10 students participate in chess club, karate club, or neither. Let event A The student is in karate club. Let event B- The student is in chess club.

One of these students is randomly selected. What is P(A/B)?

SUPER EASY A group of 10 students participate in chess club karate club or neither Let event A The student is in karate club Let event B The student is in chess class=

Respuesta :

Answer:

D.

Step-by-step explanation:

There is a total of 10 students, so let that be the denominator.

There are 3 choices (Karate club, chess club, or neither), so let that be the nominator.

3/10 = .30

Hope this helps!

Please tell me if this was correct or not :)

(D) [tex]\frac{3}{10} = 0.30[/tex]

Probability:

  • The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true.
  • An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty. The likelihood that an event will occur increases with its probability.
  • A straightforward illustration is tossing a fair (impartial) coin.
  • The coin is fair, thus the outcomes "heads" and "tails" are equally likely; the likelihood of "heads" is equal to the likelihood of "tails"; and because there are no other conceivable outcomes, the likelihood of either "heads" or "tails" is 1/2 (which is also an acceptable as 0.5 pr 50%).

Solution -

Total number or students = denominator = [tex]10[/tex]

3 choices ( karate, chess or neither ) = numerator = [tex]3[/tex]

 [tex]\frac{3}{10} = 0.30[/tex]

Therefore, [tex]P\frac{A}{B} = \frac{3}{10} = 0.30[/tex].

Know more about Probability here:

https://brainly.com/question/25870256

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