Please please help me out

Answer:
[tex]\frac{1}{2}[/tex]
Step-by-step explanation:
Using the Pythagorean identity
sin²x + cos²x = 1, then
cosx = [tex]\sqrt{1-sin^2x}[/tex]
note that ([tex]\frac{\sqrt{3} }{2}[/tex] )² = [tex]\frac{3}{4}[/tex]
cosΘ = [tex]\sqrt{1-\frac{3}{4} }[/tex] = [tex]\sqrt{\frac{1}{4} }[/tex] = [tex]\frac{1}{2}[/tex]