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Suppose line n has a slope of 5/7 and passes through (4,8). what is the equation for n in point-slope form?

Respuesta :

gmany

Answer:

[tex]\large\boxed{y-8=\dfrac{5}{7}(x-4)}[/tex]

Step-by-step explanation:

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

We have the slope [tex]m=\dfrac{5}{7}[/tex] and the point [tex](4,\ 8)[/tex].

Substitute:

[tex]y-8=\dfrac{5}{7}(x-4)[/tex]

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