Answer : The specific latent heat of fusion of ice is, 187.608 J/g
Explanation :
Formula used :
[tex]Q=m\times L_f[/tex]
where,
Q = heat supply = 863 KJ = 863000 J
conversion used : (1 KJ = 1000 J)
m = mass of the substance = 4.6 Kg = 4600 g
conversion used : (1 Kg = 1000 g)
[tex]L_f[/tex] = specific latent heat of fusion = ?
Now put all the given values in the above formula, we get the specific latent heat of fusion of ice.
[tex]863000J=4600g\times L_f[/tex]
[tex]L_f=187.608J/g[/tex]
Therefore, the specific latent heat of fusion of ice is, 187.608 J/g
