Answer:
[tex]3.6\cdot 10^{-8} N[/tex]
Explanation:
The electrostatic force between the proton and the electron is given by:
[tex]F=k\frac{q_p q_e}{r^2}[/tex]
where
[tex]k=9.00\cdot 10^9 Nm^2 C^{-2}[/tex] is the Coulomb constant
[tex]q_p = 1.6\cdot 10^{-19} C[/tex] is the magnitude of the charge of the proton
[tex]q_e = 1.6\cdot 10^{-19}C[/tex] is the magnitude of the charge of the electron
[tex]r=8\cdot 10^{-11}m[/tex] is the distance between the proton and the electrons
Substituting the values into the formula, we find
[tex]F=(9\cdot 10^9 ) \frac{(1.6\cdot 10^{-19})^2}{(8\cdot 10^{-11})^2}=3.6\cdot 10^{-8} N[/tex]
