Answer:
The area of a triangle is given by the formula:
A = bh/2
If the height of the triangle is 3 units more than the base we can say that:
h = b + 3
Therefore, the area of the triangle will be:
A= b(b+3)/2
Where 'b' comes to be the base of the triangle.
Answer:
A(b) = [tex]\frac{1}{2} (b^2 + 3b)[/tex]
Step-by-step explanation:
Given: Height of the triangle is 3 units more than the base.
Let "b" be the base of the triangle.
So, h = b + 3
Area of a triangle A = [tex]\frac{1}{2} base * height[/tex]
Now plug in h = b +3 in the above area of formula, we get
A(b) = [tex]\frac{1}{2} b*(b + 3)[/tex]
Now we can multiply b and (b + 3), we get
A(b) = [tex]\frac{1}{2} (b^2 + 3b)[/tex]
Therefore, the answer is A(b) = [tex]\frac{1}{2} (b^2 + 3b)[/tex]
