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If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

2st

2 over the quantity s times t

the quantity of 2 times s all over t

t over the quantity 2 times s

Respuesta :

meerkat18
Given:
Area = 16s²t
Length = 8st²
Width = ?

Width = Area / Length
Width = 16s²t / 8st²
Width = 2s/t ⇒ the quantity of 2 times s all over t.


JoeZD

Answer:

[tex]\frac{2s}{t}[/tex]

Step-by-step explanation:

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