Answer:
The area of triangle ABC is [tex]16\ units^{2}[/tex]
Step-by-step explanation:
we know that
The area of a triangle is equal to
[tex]A=\frac{1}{2}(b)(h)[/tex]
In this problem we have
[tex]b=AB=4-(-4)=8\ units[/tex] ---> the length of the base b is the difference of the x-coordinates between A and B
[tex]h=OC=4-0=4\ units[/tex] ---> the height h is the difference of the y-coordinates between C and the origin O
substitute the values in the formula
[tex]A=\frac{1}{2}(8)(4)[/tex]
[tex]A=16\ units^{2}[/tex]
