Explanation:
It is given that,
Wavelength, [tex]\lambda=633\ nm=633\times 10^{-9}\ m[/tex]
Slit width, [tex]a=0.5\ mm=0.0005\ m[/tex]
Order, m = 2
If the diffracted light projects onto a screen at distance 1.50 m, L = 1.5 m
For the diffraction of light,
[tex]y=\dfrac{m\lambda L}{a}[/tex]
[tex]y=\dfrac{2\times 633\times 10^{-9}\times 1.5}{0.0005}[/tex]
y = 0.0037 m
So, the distance from the center of the diffraction pattern to the dark band is 0.0037 meters. Hence, this is the required solution.
