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A baseball is popped straight up into the site and has a hang time of 6.25s determine the height to which the ball rises before it reaches its peak.

Respuesta :

MathPhys

Answer:

47.9 m

Explanation:

Given:

t = 6.25/2 = 3.125 s

v = 0 m/s

a = -9.8 m/s²

Find: Δy

Δy = vt − ½ at²

Δy = (0 m/s) (3.125 s) − ½ (-9.8 m/s²) (3.125 s)²

Δy = 47.9 m

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