In ∆ABC, if the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively, what are m < B and m
m B = 53.12°, and m C = 89.68°
Since the 3 lengths of the triangle are given, one can use the Cosine law:
b^2 = a^2 + c^2 -2ac cos(B)
18^2 = 22.5^2 + 13.6^2 -2(22.5)(13.6) cos(B)
B = 53.12 deg
Using Sine law for C
18/(sin (53.12)) = 13.6/(sin ( C))
C = 37.19 deg
