dvenezia2006
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In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA−→ and BC−→. Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs. Based on this construction, what is the measure of ∠ABC ?.

In the diagram points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA and BC Then intersecting arcs of equal size class=

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meerkat18
here are the answer choices
 m∠ABC=32°
 m∠ABC=64°
 m∠ABC=90°
 m∠ABC=128°

∠ ABC is less than 90° so the 3rd and 4th option is out.

The most likely answer is 64°. m∠ABC = 64°

32° x 2 = 64°

Answer:

Step-by-step explanation:

Alright , lets get started.

From point B, two arcs are formed, BE and BD.

From the point, E and D, two again arcs are made which are intersecting each other at point P.

It means, line BP is bisector of angle ABC.

[tex]ABC = 2 * PBE[/tex]

[tex]ABC = 2 * 32[/tex]

[tex]ABC = 64[/tex]

Hence the angle ABC is 64 degrees.   :    Answer

Hope it will help :)

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