Answer:
Angular spread, [tex]\theta=1.472\times 10^{-7}\ rad[/tex]
Explanation:
It is given that,
Wavelength of the light, [tex]\lambda=613\ nm=613\times 10^{-9}\ m[/tex]
Diameter of the telescope, D = 5.08 m
The minimum angular spread is given by :
[tex]\theta=\dfrac{1.22\lambda}{D}[/tex]
[tex]\theta=\dfrac{1.22\times 613\times 10^{-9}}{5.08}[/tex]
[tex]\theta=1.472\times 10^{-7}\ rad[/tex]
So, the minimum angular spread of the beam is [tex]1.472\times 10^{-7}\ radian[/tex]. Hence, this is the required solution.
