During World War II, tritium (3H) was a component of fluorescent watch dials and hands. Assume you have such a watch that was made in January 1944. If 16% or more of the original tritium was needed to read the dial in dark places, until what year could you read the time at night? (For 3H, t1/2 = 12.3 yr.)

Respuesta :

Answer:

1976

Explanation:

The first order decay of tritium can be represented through the following expression.

[tex]ln(\frac{[H]_{t}}{[H]_{0}} )=-k.t[/tex]

where,

[H]t is the concentration of tritium after a time t has elapsed

[H]₀ is the initial concentration of tritium

k is the rate constant

Given the half-life (t1/2) is 12.3 years, we can calculate the rate constant using the following expression.

[tex]k=\frac{ln2}{t_{1/2}} =\frac{ln2}{12.3y} =0.0564y^{-1}[/tex]

The concentration of tritium at certain time is 16% of the initial concentration, that is, [H]t = 0.16 [H]₀.

[tex]ln(\frac{0.16[H]_{0}}{[H]_{0}} )=-0.0564y^{-1}.t\\t=32y[/tex]

If the watch was made in 1944, you could read the time until 1944 + 32 = 1976.