Answer:
3,458 men
Step-by-step explanation:
The confidence interval for a normally distributed parameter can be found by:
[tex]X \pm z*\frac{s}{\sqrt n}[/tex]
Where 'X' is the population mean, 'z' is the z-value for the desire confidence (z=1.960 for 95% confidence), 's' is the standard deviation and 'n' is the sample size.
The population needed to assure that the sample mean does not differ from the true mean by more than 0.10 is:
[tex]0.10> z*\frac{s}{\sqrt n}\\\sqrt n>1.960*\frac{3.0}{0.10}\\n>3,457.4[/tex]
Rounding up to the next whole unit. The sample size must be at least 3,458 men.
