Respuesta :
Answer:
See explanation below.
Explanation:
For a general reaction, we have that the rates of appearance of products and disappearance of reactants is given by the general relationship:
aA + bB ⇒ cC + dD
- (1/a) ΔA/Δt = -(1/b) ΔB/Δt = +(1/c) ΔC/Δt = +(1/d) ΔD/Δt
For our question we can write :
- (1/a) ΔA/Δt = - (1/b) ΔB/Δt = + (1/c) ΔC/Δt
- (1/a) 0.0080 = - (1/b) 0.0120 = + (1/c) 0.0160
We can form the following equations:
(1/a)0.080 = (1/b)0.0120 ⇒ b/a = 0.0120/0.0080 = 1.5
(1/a)0.080 = (1/c)0.0160 ⇒ c/a = 0.0160/0.0080 = 2.0
(1/b)0.0120 = (1/c)0.0160 ⇒ c/b = 0.0160/0.0120 = 1.33
Given this result, we can form the following two sets of values as an example:
For a = 1, b= 1.5 = 1/2, c= 2.0
For a= 2, b= 3, and c= 4
Working with fractional coefficients, although not typical is allowed, so one can form an infinity set of coefficients with fractions and integers, even though fractional coeffients are not custumarily used.
For the general reaction, this general relationship gives us the rates of packaging design or component disappearance:
[tex]aA + bB \to cC + dD \\\\\to - (\frac{1}{a}) \frac{\Delta A}{\Delta t} = -(\frac{1}{b}) \frac{\Delta B}{\Delta t} = +(\frac{1}{c}) \frac{ \Delta C}{ \Delta t} = +(\frac{1}{d}) \frac{ \Delta D}{\Delta t}[/tex]
We can write the following in response to our question:
[tex]- (\frac{1}{a}) \frac{\Delta A}{\Delta t} = -(\frac{1}{b}) \frac{\Delta B}{\Delta t}= + (\frac{1}{c}) \frac{\Delta C}{\Delta t}\\\\ - (\frac{1}{a}) 0.0080 = -(\frac{1}{b}) 0.0120= + (\frac{1}{c}) 0.0160\\\\[/tex]
We can write the following in response to our question:
[tex](\frac{1}{a}) 0.0080 = (\frac{1}{b}) 0.0120= (\frac{b}{a}) \ \frac{0.0120}{0.0080}=1.5\\\\ (\frac{1}{a}) 0.0080 = (\frac{1}{c}) 0.0160= (\frac{c}{a}) \ \frac{0.0160}{0.0080}=2.0\\\\ (\frac{1}{a}) 0.0120 = (\frac{1}{c}) 0.0160= (\frac{c}{b}) \ \frac{0.0160}{0.0120}=1.33\\\\[/tex]
As just an example, given this result, we can build the following two sets of values:
[tex]For\ a = 1,\ b= 1.5 = \frac{1}{2},\ c= 2.0\\\\ For \ a= 2,\ b= 3,\ c= 4\\\\[/tex]
Working with fractional coefficients is permitted, despite the fact that it is uncommon so that an infinity set of coefficients can be formed using fractions and integers, despite that the fact as fractional coefficients are uncommon.
Learn more:
brainly.com/question/16654329
