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Two point-charges exert a 5 N force on each other. What will the force become if the distance between them is increased by a factor of three?

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MechEngineer

Answer:

force decreased by a factor of 9

Explanation:

According to Coulomb's law:

[tex]F_c = C\frac{C_1C_2}{R^2}[/tex]

where C1 and C2 are the charges of the 2 points. Fc is the charge force and R is the distance between them. Since the distance is squared in the denominator, if R is increased by a factor of 3, the force Fc would be decreased by a factor of [tex]3^2 = 9[/tex] times

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