Answer:
No solutions
Step-by-step explanation:
Substitute [tex]3x-9[/tex] instead of [tex]y[/tex] into the second equation:
[tex]x-\dfrac{1}{3}(3x-9)=-3[/tex]
Use distributive property to open the brackets:
[tex]x-\dfrac{1}{3}\cdot 3x+\dfrac{1}{3}\cdot 9=-3\\ \\x-x+3=-3\\ \\3=-3[/tex]
This equality is false (3 is not equal to -3), so the system of two equations has no solutions.
