Answer:
486.17 nm
Explanation:
Using the formula [tex]\frac{1}{\beta } = R__H (\frac{1}{n_1^2} - \frac{1}{n_2^2})[/tex] to calculate for the wavelength of the photon emitted. where beta means a substitute for wavelength (λ) in the above equation.
Our given parameters include ;
The Rydberg constant is 1.097 × 10-2 nm-1.
an electron drops from a 4d orbital to a 2p orbital; which implies the n₂ & n₁ respectively.
Substituting them to the above equation; we can calculate for our wavelength easily;
∴
[tex]\frac{1}{\beta}=1.097*10^{-2}(\frac{1}{2^2} - \frac{1}{4^2})[/tex]
[tex]\frac{1}{\beta}=1.097*10^{-2}*0.1875[/tex]
[tex]\frac{1}{\beta}=0.00205875[/tex]
Since we've earlier said our (β) serves as a substitute for wavelength (λ)
Thus; λ = 0.002056875⁻¹
λ = 486.174 nm
λ ≅ 486.17 nm
