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The solution set x ≤ 2 or x ≥ 4 is consistent with an equation of the form
|ax + b| ≤c, where c is greater than zero.
|ax + b| ≥ c, where c is greater than zero.
|ax + b| = c, where c is less than zero.
|−ax + b| ≤ c, where c is less than zero.

Respuesta :

frika

Answer:

B. |ax + b| ≥ c, where c is greater than zero.

Step-by-step explanation:

Given two inequalities [tex]x\le 2[/tex] and [tex]x\ge 4.[/tex]

First, make the number in right parts of both inequalities the same by absolute value. You can reach this by subtracting 3:

[tex]x\le 2\\ \\x-3\le 2-3\\ \\x-3\le -1[/tex]

and

[tex]x\ge 4\\ \\x-3\ge 4-3\\ \\x-3\ge 1[/tex]

The two inequalities [tex]x-3\le -1[/tex] and [tex]x-3\ge 1[/tex] are equivalent to the ineguality

[tex]|x-3|\ge 1[/tex]

Thus, option B is correct option.

Answer:

B

Step-by-step explanation:

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