Strength of the magnetic field: C) 20 T
Explanation:
When a conductive wire moves in a region with magnetic field, an electromotive force is induced in the wire due to the phenomenon of electromagnetic induction.
If the wire moves perpendicular to the field, the magnitude of the induced emf in the wire is given by
[tex]\epsilon=BLv[/tex]
where
B is the strength of the magnetic field
L is the length of the wire
v is the speed of the wire
For the wire in this problem, we have:
[tex]\epsilon=12 V[/tex] is the emf induced in the wire
v = 3.0 m/s is the speed of the wire
L = 0.20 m is its length
Solving for B, we find the strength of the magnetic field:
[tex]B=\frac{\epsilon}{Lv}=\frac{12}{(0.20)(3.0)}=20 T[/tex]
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