A spring AB of constant k is attached to a support at A and to a collar of mass m. The unstretched length of the spring is l. Knowing that the collar is released from rest at x 5 x0 and neglecting friction between the collar and the horizontal rod, determine the magnitude of the velocity of the collar as it passes through point C.

In this case, when the collar mass is released, it will move from the rest point, to a point between A and B and then to point C. While it approaches point C, the amount of stretch will decrease and the spring force will reduce.At point C, the spring reaches its maximum stretch, leaving un-stretched length of spring l, making point C the position where the velocity of the collar is maximum.The energy possessed due to motion of the collar is kinetic energy, thus the magnitude of the velocity can be calculated from;

Kinetic energy, K.E = 1/2*m*v²

Thus

[tex]v=\sqrt{\frac{K.E}{0.5m} }[/tex]

where m is mass of collar and v is speed of collar. The faster the collar the more the kinetic energy.

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Spring kinetic energy :https://brainly.com/question/13866407

Keywords :spring, spring constant, support, collar mass, unstretched length, friction, horizontal rod

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