Answer:
The correct answer is;
2. less than 15 s
Explanation:
Grahams law of effusion states
[tex]\frac{Rate 1}{Rate2} =\sqrt{\frac{Molar Mass2}{MolarMass 1} }[/tex]
Therefore
we have molar mass of neon gas = 20.18 g/mol
Molar mass of nitrogen gas = 28.014 g/mol
Which gives
[tex]\frac{Rate 1}{15} =\sqrt{\frac{20.18}{28.014} }[/tex] = 0.72
Therefore the rate of effusion of nitrogen gas is 0.72*15 = 12.73 s which is less than 15 s
