Respuesta :
Answer:
The magnitude of the force is [tex]7.2\times10^{-16}\ N[/tex]
Explanation:
Given that,
Electric field intensity [tex]E= 4.5\times10^3[/tex]
Suppose, The electron when positioned at this location
We need to calculate the magnitude of the force
Using formula of electric field
[tex]E = \dfrac{F}{q}[/tex]
[tex]F = Eq[/tex]
Where, E = electric field
q = charge of electron
Put the value into the formula
[tex]F=4.5\times10^3\times1.6\times10^{-19}[/tex]
[tex]F=7.2\times10^{-16}\ N[/tex]
Hence, The magnitude of the force is [tex]7.2\times10^{-16}\ N[/tex]
Answer:
Explanation:
Electric field, E = 4.5 x 10^3 N/C
charge on electron, e = 1.6 x 10^-19 C
The relation between the force and the electric field is given by
F = q E
F = 1.6 x 10^-19 x 4.5 x 10^3
F = 7.2 x 10^-16 N
