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A cart of mass 0.400 kg moves with a speed of 1.2 m/s toward a secondary cart of mass 0.300 kg that is initially at rest. When the carts collide they stick together. What speed do the carts move with after the collision

Respuesta :

adelekeademolu

Answer:

0.686 m/s

Explanation:

The principle of conservation says the sum of momenta before collision is equal to the sum of momenta after collision in an isolated system. Here, we assume the system is not acted upon by any external force.

The initial momentum = momentum of 1 st cart + momentum of 2nd cart

                                     = 0.400 × 1.2 + 0.300 × 0 = 0.48 kg m/s

The final momentum = (0.400 + 0.300) × v   (since they stick together)

0.700 v = 0.48

v = 0.686 m/s

Lanuel

The speed with which the carts move after the collision is equal to 0.69 m/s.

Given the following data:

  • Mass of cart 1 = 0.400 kg
  • Speed of cart 1 = 1.2 m/s
  • Mass of cart 2 = 0.300 kg
  • Speed of cart 2 = 0 m/s (since it is initially at rest).

To calculate the speed with which the carts move after the collision:

Applying the law of conservation of momentum, the collision between the two carts is given by the formula:

[tex]M_1V_1 + M_2V_2 = V_f(M_1 + M_2)[/tex]

Where:

  • M is the mass of cart.
  • V is the velocity of cart.

Substituting the given parameters into the formula, we have;

[tex]0.400 \times 1.2 + 0.300 \times 0 = V_f(0.400 + 0.300)\\\\0.48+0=V_f(0.700)\\\\0.48=0.700V_f\\\\V_f=\frac{0.48}{0.700} \\\\V_f=0.69 \;m/s[/tex]

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