How much work is required to move an electron from the positive terminal to the negative terminal of a 12 V battery? (Knight 21.4) A 20 nC charge is moved from a point where V=150V to point where V=-50V. How much work is done to move the charge?

Respuesta :

Answer:

work which is required to move an electron from the positive terminal to the negative terminal is

-4μJ

W = -4μJ

Explanation:

Work required to move the charge

W = qΔV

initial point V₁ = 150V

Final point V₂ = -50V

W = q(V₂ -V₁)

= 20 × 10⁹(-50 - 150)

W = -4μJ

work which is required to move an electron from the positive terminal to the negative terminal is

-4μJ