A three-phase bridge rectifier is used to provide DC power. The input voltage is 277/480V three phase. Determine the DC voltage output and harmonic content.

Respuesta :

Answer:

Explanation:

DC output voltage, V₀

[tex]V_{o} = 3V_{p} /\pi \\V_{p} = \sqrt{2}V_{rms} \\V_{rms} = 480\\V_{p} = \sqrt{2} * 480\\V_{p} = 678.82 V\\V_{o} = 3*678.82 /\pi\\V_{o} = 648.23 V[/tex]

To get the output rms voltage

Answer:

  • Dc voltage output : 648.23 v
  • Harmonic content : 27.19 v

Explanation:

The DC voltage output can be calculated using this formula

Vo = 3Vp / π

Vp = [tex]\sqrt{2Vrms}[/tex]

Vrms = 480 v

therefore Vp = [tex]\sqrt{2 * 480}[/tex] = 678.82 v

Vodc = (3*678.82) / (22/7) = 648.23 V ( dc voltage output )

The harmonic content is calculated as

H = [tex]\sqrt{Vorms^{2} - Vodc^{2} }[/tex]

Vorms = [tex]\frac{\sqrt{2Vrms*1.383} }{\frac{2*3.14}{3} }[/tex] = 648.797

back to initial equation

H = [tex]\sqrt{648.797^{2} - 648.23^{2} }[/tex]

H = 27.19 v