contestada

If 0.507 moles of zinc reacts with excess lead(IV) sulfate, how many grams of zinc sulfate would be produced in the following reaction?

Respuesta :

daniel987
so first write the equation: PbSO4 + 2Zn ----> 2ZnSO4 + Pb
if we have 0.507 moles of zinc and the lead sulfate isnt limiting then we just go between ratios 2:2 so its a 1:1 ratio

so all that needs to be done is to find the mass of ZnSO4 using an equation
mass = moles x RFM
mass of ZnSO4 = 0.507 x 161.45
mass of ZnSO4 = 81.85g
hope that helps

Otras preguntas