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The combustion of a sample of butane, C4H10 (lighter fluid), produced 2.46 grams of water. 2 C4H10 + 13 O2 -------> 8 CO2 + 10 H2O (a) How many moles of water formed? (b) How many moles of butane burned? (c) How many grams of butane burned? (d) How much oxygen was used up in moles? In grams?

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meerkat18
we are given with the amount of water produced in the reaction. In this case, we convert this into moles to conveniently find out other values of the compounds. In this case, a)0.1367 moles H20b)0.01367 moles butanec)0.7927 grams butaned)0.1776 moles O2 and 5.69 grams O2

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