unheated
heated
The unheated gas in the above system has a volume of 20.0L
at a temperature of 25.0°C and a pressure of 1.00 atm. The
gas is heated to a temperature of 100.0 °C while the volume
remains constant. What is the pressure of the heated gas?
Ignore the block labeled "A".

Respuesta :

Explanation:

Using the Combined Gas Law, which is:

[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]

(With [tex]P_1,V_1,T_1[/tex] being initial pressure, volume and temperature; and

[tex]P_2,V_2,T_2[/tex] being the new values)

We can move the units around in order to solve for [tex]P_2[/tex], which would look like this:

[tex]P_{2} =\frac{P_1V_1T_2}{V_2T_1}[/tex]

Then we convert the Celsius temperature to Kelvin:

[tex]25[/tex] °[tex]C[/tex] = [tex]289[/tex] [tex]K[/tex]

[tex]100[/tex] °[tex]C[/tex] = [tex]373[/tex] [tex]K[/tex]

And now, we plug in all of the values and solve, with volume remaining as a constant:

[tex]P_{2} =\frac{(1.00 atm) (20.0 L) (373 K)}{(20.0 L) (298 K)}[/tex] [tex]=[/tex]

[tex]1.25[/tex] [tex]atm[/tex] or [tex]127[/tex] [tex]kPa[/tex]

Answer:1.25

Explanation:

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