Determine the temperature of 2.49mol of a gas contained in a 1.00L vessel at a pressure of 1.41atm.

A. 345K

B. 159K

C. 18.7K

D. 6.90K

Respuesta :

Answer: T=6.90 K

Explanation:

For this problem, you would use Ideal Gas Law.

[tex]PV=nRT[/tex]

P=pressure

V=volume

n=moles

R=ideal gas constant

T=temperature (in Kelvin)

We can fill in these values with what we are given.

P=1.41 atm

V=1.00 L

n=2.49 mol

R=0.08206 Latm/Kmol

T=?K

Since we are looking for T, we can get T alone.

[tex]T=\frac{PV}{nR}[/tex]

[tex]T=\frac{(1.41 atm)(1.00L)}{(2.49mol)(0.08206Latm/Kmol)}[/tex]

[tex]T=6.9006 K[/tex]

With significant figures, we get [tex]T=6.90 K[/tex].