Answer:
Immediately after the switches closes, the capacitor voltage is zero.
Explanation:
Charge on capacitor is given as;
[tex]q_o = CV_{battery}[/tex]
after the switches closes, the charge on the capacitor is the same as before, therefore, the voltage drop in the capacitor is zero.
Apply Kirchoff's voltage rule for short term;
[tex]q = q_o[/tex] = 0 (since it is uncharged)
[tex]V_{battery} + IR =0[/tex]
Where;
q₀ is the charge on the capacitor before
q is the charge on the capacitor after
Therefore, immediately after the switches closes, the capacitor voltage is zero.
