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15.) In a laboratory, the count of bacteria in a certain
experiment was increasing at the rate of 2.5% per
hour. Find the bacteria at the end of two hours if the
count initially was 4,80,000.

PLZ answer it's urgent plz ​

Respuesta :

Answer:

Step-by-step explanation:

given,

initial count of bacteria(P)=4,80,000 ,

increasing rate of bacteria(R)=2.5%,

time(T)= 2 hours

amount(A)=p(1+R/100)^T

A=480000(1+2.5/100)^2

A=480000*(1681/1600)

A=504300

therefore, the bacteria at the end of 2 hours is 504300(approx)

Answer:

itchkirdcbn

Step-by-step explanation:

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