Answer:
200 N
Explanation:
Assume that counterclockwise is positive and clockwise is negative.
The 500 N load is 0.5 m from the fulcrum, so the effort force F on the other end is 1.25 m from the fulcrum.
Sum of the torques about the fulcrum equal 0.
∑τ = Iα
(500 N) (0.5 m) − F (1.25 m) = 0
F = 200 N
