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You intend to estimate a population mean μ with the following sample. 78.4, 85.3, 50, 68.4, 59.4, 73.7, 73.2, 47.4, 40.5
You believe the population is normally distributed.
Find the 99.5% confidence interval.
The answer must be done as an open-interval accurate to 2 decimal places.

Respuesta :

MathPhys

Answer:

(17.75, 110.32)

Step-by-step explanation:

The sample mean is 64.03, and the standard deviation is 15.43.

The population is normally distributed, so 99.5% confidence is ±3 standard deviations.

The confidence interval is therefore:

(64.03 − 3 × 15.43, 64.03 + 3 × 15.43)

(17.75, 110.32)

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