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The volume of a sample of gas measured at 27 °C is 10.0 dm . What is the temperature when the volume is reduced to 9.0 dm at the same pressure?

Respuesta :

The second temperature of the sample of gas is 24.3°C

The calculation can be done as follows

T1= 27 °c

T2= ?

V1= 10 dm

V2= 9 dm

V1/T1= V2/T2

10/27= 9/T2

Cross multiply

10 ×T2= 9 × 27

T2= 9 × 27/10

= 243/10

= 24.3 °C

Hence the second temperature is 24.3°C

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