PLEASEEE HELP!!! Let f and g be differentiable functions such that f' (1) = 2 and g’ (1) = 6. If h (x) = 5 f(x) - 4g (x) + 3x^2 - 2, what is the value of h’ (1) ?

The value of h'(1) is -8
Given the following expression;
[tex]h (x) = 5 f(x) - 4g (x) + 3x^2 - 2[/tex]
Differentiating the function above:
[tex]h' (x) = 5 f'(x) - 4g' (x) + 6x[/tex]
Given the following parameters
[tex]f' (1) = 2\\g' (1) = 6[/tex]
Get h'(1)
[tex]h' (1) = 5 f'(1) - 4g' (1) + 6(1)\\h' (1)=5 (2) - 4(6) + 6(1)\\h' (1)= 10-24+6\\h' (1)=-8[/tex]
Hence the value of h'(1) is -8
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